___?____ times the sum of the squares of sides of a triangle is equal to four times the sum of the square of the medians of the same triangle?

____?____ times the sum of the squares of sides of a triangle is equal to four times the sum of the square of the medians of the same triangle?

Solution: Let, the be triangle be a equilateral triangle ABC as follows

AO, BM and CN are the medians of the triangle.
Here, they are all equal.
Three times of the  sum of the squares of sides of a triangle=3(3a^2)=9a^2=a^2-(a/2)^2........(1)
Four times the sum of the square of the medians of the same triangle=4[3{a^2-(a/2)^2}]=9a^2....(2)
Therefore, (1)=(2)......solved.