If x/(b -c)(b+c—2a)= y/(c -a)(c+a-2b)= z/(a -b)(a+b-2c) then the value of (x + y * z) is?

If x/(b -c)(b+c—2a)= y/(c -a)(c+a-2b)= z/(a -b)(a+b-2c)

then the value of (x + y * z) is?

Solution :Let all three ratios are equal to a constant value of K
Then it goes like 

1. X=K{(b -c)(b+c—2a)}
2. Y=K{(c -a)(c+a-2b)}
3. C=K{(a -b)(a+b-2c)}

Then adding X,Y and Z would be =K{(b -c)(b+c—2a)+(c -a)(c+a-2b)+(a -b)(a+b-2c)}=KX0=0(Answer).